We know that:
\[ \sin^2 \theta + \cos^2 \theta = 1 \]
The given expression is:
\[ \sin^2 \theta + \sin \theta + \cos^2 \theta = 1 + \sin \theta \]
For this to equal 2:
\[ 1 + \sin \theta = 2 \implies \sin \theta = 1 \]
The value of \(\theta\) for which \(\sin \theta = 1\) is \(90^\circ\).