For the matrix A=\(\begin{bmatrix}1&5\\6&7\end{bmatrix}\),verify that
I. (A+A') is a symmetric matrix
II. (A-A') is a skew symmetric matrix
A'= \(\begin{bmatrix}1&6\\5&7\end{bmatrix}\)
(i)A+A'=\(\begin{bmatrix}1&5\\6&7\end{bmatrix}\)+\(\begin{bmatrix}1&6\\5&7\end{bmatrix}\)
=\(\begin{bmatrix}2&11\\11&14\end{bmatrix}\)
therefore (A+A')'= \(\begin{bmatrix}2&11\\11&14\end{bmatrix}\)=A+A'
Hence,(A+A') is a symmetric matrix.
(ii)A-A'= \(\begin{bmatrix}1&5\\6&7\end{bmatrix}\)-\(\begin{bmatrix}1&6\\5&7\end{bmatrix}\)
=\(\begin{bmatrix}0&-1\\1&0\end{bmatrix}\)
(A-A')'=\(\begin{bmatrix}0&1\\-1&0\end{bmatrix}\)=-\(\begin{bmatrix}0&-1\\1&0\end{bmatrix}\)=-(A-A')
Hence,(A-A') is a skew-symmetric matrix.
A certain reaction is 50 complete in 20 minutes at 300 K and the same reaction is 50 complete in 5 minutes at 350 K. Calculate the activation energy if it is a first order reaction. Given: \[ R = 8.314 \, \text{J K}^{-1} \, \text{mol}^{-1}, \quad \log 4 = 0.602 \]