
| A | B | X |
|---|---|---|
0 0 1 1 | 0 1 0 1 | 1 0 0 0 |
| A | B | X |
|---|---|---|
0 0 1 1 | 0 1 0 1 | 0 1 1 1 |
| A | B | X |
|---|---|---|
0 0 1 1 | 0 1 0 1 | 0 1 1 0 |
| A | B | X |
|---|---|---|
0 0 1 1 | 0 1 0 1 | 1 0 1 0 |
The given circuit consists of a combination of NOT, AND, and OR gates. The truth table is derived as follows:
1. The NOT gates invert the inputs \(A\) and \(B\).
2. These inverted values are then input into the AND gates, and the output of each AND gate is determined.
3. Finally, the outputs of the AND gates are fed into the OR gate to produce the final output \(X\).
Truth Table Analysis:
(A) When \(A = 0\) and \(B = 0\), the output \(X = 1\).
(B) When \(A = 0\) and \(B = 1\), the output \(X = 0\).
(C) When \(A = 1\) and \(B = 0\), the output \(X = 1\).
(D) When \(A = 1\) and \(B = 1\), the output \(X = 0\).
Hence, the correct truth table corresponds to Table 3.

The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
Consider the following logic circuit.
The output is Y = 0 when :

Let $ A \in \mathbb{R} $ be a matrix of order 3x3 such that $$ \det(A) = -4 \quad \text{and} \quad A + I = \left[ \begin{array}{ccc} 1 & 1 & 1 \\2 & 0 & 1 \\4 & 1 & 2 \end{array} \right] $$ where $ I $ is the identity matrix of order 3. If $ \det( (A + I) \cdot \text{adj}(A + I)) $ is $ 2^m $, then $ m $ is equal to:
A square loop of sides \( a = 1 \, {m} \) is held normally in front of a point charge \( q = 1 \, {C} \). The flux of the electric field through the shaded region is \( \frac{5}{p} \times \frac{1}{\varepsilon_0} \, {Nm}^2/{C} \), where the value of \( p \) is: