Question:

For the given logic gates combination, the correct truth table will be
For the given logic gates combination,the correct truth table will be

Updated On: Mar 20, 2025
  • ABX

    0

    0

    1

    1

    0

    1

    0

    1

    1

    0

    0

    0

  • ABX

    0

    0

    1

    1

    0

    1

    0

    1

    0

    1

    1

    1

  • ABX

    0

    0

    1

    1

    0

    1

    0

    1

    0

    1

    1

    0

  • ABX

    0

    0

    1

    1

    0

    1

    0

    1

    1

    0

    1

    0

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The Correct Option is C

Solution and Explanation

The given circuit consists of a combination of NOT, AND, and OR gates. The truth table is derived as follows:
1. The NOT gates invert the inputs \(A\) and \(B\).
2. These inverted values are then input into the AND gates, and the output of each AND gate is determined.
3. Finally, the outputs of the AND gates are fed into the OR gate to produce the final output \(X\).
Truth Table Analysis:
(A) When \(A = 0\) and \(B = 0\), the output \(X = 1\). 

(B) When \(A = 0\) and \(B = 1\), the output \(X = 0\). 

(C) When \(A = 1\) and \(B = 0\), the output \(X = 1\). 

(D) When \(A = 1\) and \(B = 1\), the output \(X = 0\). 

Hence, the correct truth table corresponds to Table 3.

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