
| A | B | X |
|---|---|---|
0 0 1 1 | 0 1 0 1 | 1 0 0 0 |
| A | B | X |
|---|---|---|
0 0 1 1 | 0 1 0 1 | 0 1 1 1 |
| A | B | X |
|---|---|---|
0 0 1 1 | 0 1 0 1 | 0 1 1 0 |
| A | B | X |
|---|---|---|
0 0 1 1 | 0 1 0 1 | 1 0 1 0 |
The given circuit consists of a combination of NOT, AND, and OR gates. The truth table is derived as follows:
1. The NOT gates invert the inputs \(A\) and \(B\).
2. These inverted values are then input into the AND gates, and the output of each AND gate is determined.
3. Finally, the outputs of the AND gates are fed into the OR gate to produce the final output \(X\).
Truth Table Analysis:
(A) When \(A = 0\) and \(B = 0\), the output \(X = 1\).
(B) When \(A = 0\) and \(B = 1\), the output \(X = 0\).
(C) When \(A = 1\) and \(B = 0\), the output \(X = 1\).
(D) When \(A = 1\) and \(B = 1\), the output \(X = 0\).
Hence, the correct truth table corresponds to Table 3.
Which of the following circuits has the same output as that of the given circuit?




For the circuit shown above, the equivalent gate is:

To obtain the given truth table, the following logic gate should be placed at G:
For the AC circuit shown in the figure, $ R = 100 \, \text{k}\Omega $ and $ C = 100 \, \text{pF} $, and the phase difference between $ V_{\text{in}} $ and $ (V_B - V_A) $ is 90°. The input signal frequency is $ 10^x $ rad/sec, where $ x $ is:
Two parabolas have the same focus $(4, 3)$ and their directrices are the $x$-axis and the $y$-axis, respectively. If these parabolas intersect at the points $A$ and $B$, then $(AB)^2$ is equal to:
A point particle of charge \( Q \) is located at \( P \) along the axis of an electric dipole 1 at a distance \( r \) as shown in the figure. The point \( P \) is also on the equatorial plane of a second electric dipole 2 at a distance \( r \). The dipoles are made of opposite charge \( q \) separated by a distance \( 2a \). For the charge particle at \( P \) not to experience any net force, which of the following correctly describes the situation?
