4 g of C3H4 = 0.1 mol
From 0.1 mol of P, 0.01 mol of R will be produced
\(⇒ 1.62 \) g of R is produced
From 0.1 mol of P, 0.032 mol of U is produced
\(= 3.2 \)g of U is produced
During "S" estimation, 160 mg of an organic compound gives 466 mg of barium sulphate. The percentage of Sulphur in the given compound is %.
(Given molar mass in g mol\(^{-1}\) of Ba: 137, S: 32, O: 16)