Question

For the following compound

the number of signals expected in the 1H NMR spectrum is _________.

Answer 1

Correct Answer: 2

In the given compound, we have two distinct types of protons:

1. The two methoxy groups (−OCH₃) each have identical protons, and they are chemically equivalent.
2. The protons on the benzene ring are all equivalent because of the symmetry of the structure (with methoxy groups at the ortho positions relative to each other).

Therefore, the ¹H NMR spectrum will exhibit two signals:

1. A signal for the methoxy protons (OCH₃).
2. A signal for the aromatic protons on the benzene ring.

Thus, the correct number of signals is 2