Step 1: Applying the Nernst equation.
We can use the Nernst equation to solve for the potential of the silver electrode. The standard cell potential is related to the potentials of the half-reactions by:
\[
E_{\text{cell}} = E_{\text{cathode}} - E_{\text{anode}}
\]
Here, Cu\(^{2+}\) / Cu is the anode and Ag\(^+\) / Ag is the cathode. Thus,
\[
0.463 = E_{\text{Ag}} - 0.337 \quad \Rightarrow \quad E_{\text{Ag}} = 0.800 \, \text{V}
\]
Step 2: Conclusion.
The standard potential of the silver electrode is (B) 0.800 V.