Question

For the compounds given below, the CORRECT order of increasing oxidation number of I is:

• A. \( \text{ICl}<\text{HI}<\text{HIO}_3 \)
• B. \( \text{HI}<\text{ICl}<\text{HIO}_2<\text{KIO}_3 \)
• C. \( \text{HIO}_2<\text{ICl}<\text{HI}<\text{KIO}_3 \)
• D. \( \text{KIO}_3<\text{HIO}_2<\text{ICl}<\text{HI} \)

Hint:

Remember, in compounds like \( \text{HI}, \text{ICl}, \text{HIO}_3, \text{KIO}_3 \), the oxidation number of iodine increases as it moves from \( -1 \) to \( +5 \). The more oxygen atoms present, the higher the oxidation state.

Answer 1

The Correct Option is B

The oxidation states of iodine in the given compounds are as follows:
- In \( \text{HI} \), iodine has an oxidation state of \(-1\).
- In \( \text{ICl} \), iodine has an oxidation state of \(-1\).
- In \( \text{HIO}_3 \), iodine has an oxidation state of \(+5\).
- In \( \text{HIO}_2 \), iodine has an oxidation state of \(+3\).
- In \( \text{KIO}_3 \), iodine has an oxidation state of \(+5\).
Thus, the correct order of increasing oxidation states of iodine is: \[ \text{HI}<\text{ICl}<\text{HIO}_2<\text{KIO}_3 \]