Question:
For the compounds:
(A) \( \text{H}_3\text{C} - \text{CH}_2 - \text{O} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \)
(B) \( \text{H}_3\text{C} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \)
(C) \( \text{CH}_3 - \text{CH}_2 - \text{C} - \text{CH}_2 - \text{CH}_3 \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ||\ \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{O}\ \) (D) \( \text{H}_3\text{C} - \text{CH} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\ \)
The increasing order of boiling point is: Choose the correct answer from the options given below:
For the compounds:
(A) \( \text{H}_3\text{C} - \text{CH}_2 - \text{O} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \)
(B) \( \text{H}_3\text{C} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \)
(C) \( \text{CH}_3 - \text{CH}_2 - \text{C} - \text{CH}_2 - \text{CH}_3 \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ||\ \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{O}\ \)
(A) \( \text{H}_3\text{C} - \text{CH}_2 - \text{O} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \)
(B) \( \text{H}_3\text{C} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \)
(C) \( \text{CH}_3 - \text{CH}_2 - \text{C} - \text{CH}_2 - \text{CH}_3 \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ||\ \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{O}\ \)
(D) \( \text{H}_3\text{C} - \text{CH} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\ \)
The increasing order of boiling point is: Choose the correct answer from the options given below:
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\ \)
\(\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH}\ \)
The increasing order of boiling point is: Choose the correct answer from the options given below:
Updated On: Nov 21, 2024
- (A)<(B)<(C)<(D)
- (B)<(A)<(C)<(D)
- (D)<(C)<(A)<(B)
- (B)<(A)<(D)<(C)
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Compounds having the same number of carbon atoms follow the boiling point order as:
\((\text{Boiling point})_{\text{Hydrogen bonding}} > (\text{Boiling point})_{\text{High polarity}} > (\text{Boiling point})_{\text{Low polarity}} > (\text{Boiling point})_{\text{Non-polar}}\)
Was this answer helpful?
0
0
Top Questions on Organic Chemistry
- Valency of atom C in C_6H_6 is
- UP Board - 2025
- Science
- Organic Chemistry
- Homologous series among the following is:
- UP Board - 2025
- Science
- Organic Chemistry
- Given below are two statements: Statement I: One mole of propyne reacts with excess of sodium to liberate half a mole of H₂ gas. Statement II: Four g of propyne reacts with NaNH₂ to liberate NH₃ gas which occupies 224 mL at STP. In the light of the above statements, choose the most appropriate answer from the options given below:
- JEE Main - 2025
- Chemistry
- Organic Chemistry
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
- JEE Main - 2025
- Chemistry
- Organic Chemistry
- Identify A and B in each of the following reaction sequence:
(a) \[ CH_3CH_2Cl \xrightarrow{NaCN} A \xrightarrow{H_2/Ni} B \]
(b) \[ C_6H_5NH_2 \xrightarrow{NaNO_2/HCl} A \xrightarrow{C_6H_5NH_2} B \]- CBSE CLASS XII - 2025
- Chemistry
- Organic Chemistry
View More Questions
Questions Asked in JEE Main exam
- At the interface between two materials having refractive indices \( n_1 \) and \( n_2 \), the critical angle for reflection of an EM wave is \( \theta_c \). The \( n_1 \) material is replaced by another material having refractive index \( n_3 \), such that the critical angle at the interface between \( n_1 \) and \( n_3 \) materials is \( \theta_{c3} \). If \( n_1 > n_2 > n_3 \), \( \frac{n_2}{n_3} = \frac{2}{5} \), and \( \sin \theta_{c2} - \sin \theta_{c1} = \frac{1}{2} \), then \( \theta_{c1} \) is:
- JEE Main - 2025
- Refraction of Light
- Let the lines \[ 3x - 4y - \alpha = 0, \quad 8x - 11y - 33 = 0, \quad 2x - 3y + \lambda = 0 \] be concurrent. If the image of the point \( (1, 2) \) in the line \[ 2x - 3y + \lambda = 0 \text{ is } \left( \frac{57}{13}, \frac{-40}{13} \right), \text{ then } |\alpha \lambda| \text{ is equal to:} \]
- JEE Main - 2025
- Matrices and Determinants
- Potential energy is not defined for which of the following forces?
- A compound 'X' absorbs 2 moles of hydrogen and 'X' upon oxidation with KMnO4 - H⁺ gives the following products:
- JEE Main - 2025
- Organic Compounds and Hydrogenation
- Consider the above reaction, what mass of CaCl₂ will be formed if 250 ml of 0.76 M HCl reacts with 1000 g of CaCO₃?
- JEE Main - 2025
- Stoichiometry and Stoichiometric Calculations
View More Questions