Question

For the circuit shown in the figure, the current through the inductor is \( 0.9A \) while the current through the condenser is \( 0.4A \). Then: 
 

• A. Current drawn from source \( I = 1.13A \)
• B. \( \omega = \frac{1}{1.5LC} \)
• C. \( I = 0.5A \)
• D. \( I = 0.6A \)

Hint:

For AC circuits:
- The net current is found using \( I = \sqrt{I_L^2 + I_C^2} \).
- The phase difference between inductor and capacitor currents must be considered.

Answer 1

The Correct Option is C

To determine the total current drawn from the source, we analyze the given circuit using phasor analysis.
Step 1: Given Data
- Current through the inductor: \( I_L = 0.9A \)
- Current through the capacitor: \( I_C = 0.4A \)
Step 2: Phasor Representation of Currents
In an AC circuit, the currents through the inductor and capacitor are out of phase with each other by \( 180^\circ \), meaning they oppose each other. The net reactive current is given by:
\[ I_{{reactive}} = I_L - I_C \] \[ I_{{reactive}} = 0.9A - 0.4A = 0.5A \] Step 3: Total Current Calculation
The total current \( I \) drawn from the source is the resultant of the resistive current and the net reactive current. However, since no resistive component is mentioned, the current drawn from the source is simply:
\[ I = I_{{reactive}} = 0.5A \] Thus, the correct answer is:
\[ {I = 0.5A} \]