Given: The formula for the radius \( r \) is:
\(r = 52.9 \times \frac{n^2}{z} \,\, \text{pm}\)
From the equation:
\(\therefore 105.8 = \frac{52.9 \times n^2}{2} \,\,\, \therefore n_2 = 2\)
Similarly, for \( n_1 \):
\(26.45 = 52.9 \times \frac{n^2}{2} \,\,\, \therefore n_1 = 1\)
The energy change \( \Delta E \) is given by:
\(\Delta E = R_H h C \times z^2 \left[ \frac{1}{n_1^2} - \frac{1}{n_2^2} \right]\)
Using the equation for wavelength, we have:
\(\frac{hc}{\lambda} = R_H h C \times z^2 \left[ \frac{1}{n_1^2} - \frac{1}{n_2^2} \right]\)
Substituting the known values:
\(\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{\lambda} = 2.2 \times 10^{-18} \times 4 \times \frac{3}{4}\)
Solving for \( \lambda \):
\(\therefore \lambda = 300 \, \text{Å}\)
Finally, converting to nanometers:
\(\therefore \lambda = 30 \, \text{nm}\)
The wavelength of the emitted photon is 30 nm.
The center of a disk of radius $ r $ and mass $ m $ is attached to a spring of spring constant $ k $, inside a ring of radius $ R>r $ as shown in the figure. The other end of the spring is attached on the periphery of the ring. Both the ring and the disk are in the same vertical plane. The disk can only roll along the inside periphery of the ring, without slipping. The spring can only be stretched or compressed along the periphery of the ring, following Hooke’s law. In equilibrium, the disk is at the bottom of the ring. Assuming small displacement of the disc, the time period of oscillation of center of mass of the disk is written as $ T = \frac{2\pi}{\omega} $. The correct expression for $ \omega $ is ( $ g $ is the acceleration due to gravity): 
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
The solutions can be classified into three types:
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types: