The power (P) of a lens is given by the lensmaker's formula:
P = (μ - 1) (1/R1 - 1/R2)
Where:
If the radii of curvature (R1 and R2) are fixed, then (1/R1 - 1/R2) is a constant. Let's call this constant K.
So, the formula becomes:
P = (μ - 1)K
Since K is a constant, we can say that:
P ∝ (μ - 1)
Therefore, for fixed values of radii of curvature of the lens, the power of the lens is proportional to (μ - 1).
The correct answer is:
Option 1: P ∝ (μ - 1)
In the diagram given below, there are three lenses formed. Considering negligible thickness of each of them as compared to \( R_1 \) and \( R_2 \), i.e., the radii of curvature for upper and lower surfaces of the glass lens, the power of the combination is: