Question

For decolourisation of 1 mole of KMnO\(_4\), the moles of H\(_2\)O\(_2\) required is:

• A. \( \frac{1}{2} \)
• B. \( \frac{3}{2} \)
• C. \( \frac{5}{2} \)
• D. \( \frac{7}{2} \)

Hint:

For reaction stoichiometry, use the coefficients from the balanced equation to find the mole ratio.

Answer 1

The Correct Option is C

The reaction for decolourisation of KMnO\(_4\) with H\(_2\)O\(_2\) is: \[ 2KMnO_4 + 3H_2O_2 + 4H_2O \rightarrow 2MnO_2 + 3O_2 + 4KOH \] From the stoichiometry, 3 moles of H\(_2\)O\(_2\) are required for every 2 moles of KMnO\(_4\). Therefore, for 1 mole of KMnO\(_4\), the required moles of H\(_2\)O\(_2\) will be \( \frac{3}{2} \). Thus, the correct answer is Option (C).