For a uniformly charged thin spherical shell of radius \( R \) and total charge \( Q \), the electric potential inside the shell (\( r < R \)) is constant and equal to the potential at the surface:
\( V = \frac{kQ}{R} \)
where \( k \) is Coulomb's constant. This means the potential does *not* change as you move from the center towards the surface.
For points outside the shell (\( r > R \)), the electric potential is the same as that of a point charge located at the center of the shell:
\( V = \frac{kQ}{r} \)
The potential decreases as the distance \( r \) increases, following an inverse relationship.
Based on the above analysis:
This corresponds to a graph that is constant for \( r < R \) and then decreases hyperbolically for \( r > R \).
The correct graphical representation is Option (4).
Find the equivalent capacitance between A and B, where \( C = 16 \, \mu F \).
If the equation of the parabola with vertex \( \left( \frac{3}{2}, 3 \right) \) and the directrix \( x + 2y = 0 \) is \[ ax^2 + b y^2 - cxy - 30x - 60y + 225 = 0, \text{ then } \alpha + \beta + \gamma \text{ is equal to:} \]