Question:

For a thermodynamic system, the coefficient of volume expansion \(\beta=\frac{1}{V}(\frac{βˆ‚V}{βˆ‚T})_P\) and compressibility \(K=-\frac{1}{V}(\frac{βˆ‚V}{βˆ‚P})_T\) , where V, T, and P are respectively the volume, temperature, and pressure. Considering that \(\frac{dV}{V}\) is a perfect differential, we get

Updated On: Oct 1, 2024
  • \((\frac{βˆ‚\beta}{βˆ‚P})_T=(\frac{βˆ‚K}{βˆ‚T})_P\)
  • \((\frac{βˆ‚\beta}{βˆ‚T})_P=-(\frac{βˆ‚K}{βˆ‚P})_T\)
  • \((\frac{βˆ‚\beta}{βˆ‚P})_T=-(\frac{βˆ‚K}{βˆ‚T})_P\)
  • \((\frac{βˆ‚\beta}{βˆ‚T})_P=(\frac{βˆ‚K}{βˆ‚P})_T\)
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The Correct Option is C

Solution and Explanation

The correct option is (C) : \((\frac{βˆ‚\beta}{βˆ‚P})_T=-(\frac{βˆ‚K}{βˆ‚T})_P\).
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