Question:
For a series LCR circuit, at the condition of resonance, the value of the power factor will be:
For a series LCR circuit, at the condition of resonance, the value of the power factor will be:
Updated On: Mar 27, 2025
- Zero
- 1
- 0.2
- 0.5
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The Correct Option is B
Solution and Explanation
Series LCR Circuit at Resonance:
- At resonance: Inductive reactance (XL) = Capacitive reactance (XC)
- Net impedance becomes purely resistive: Z = R (minimum impedance)
- Phase difference (φ) between current and voltage becomes zero
Power Factor Calculation:
Power factor = cosφ = R/|Z|
At resonance:
|Z| = √[R² + (XL - XC)²] = R (since XL = XC)
∴ Power factor = cosφ = R/R = 1
Final Answer: The power factor will be 1 (unity) at resonance.
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