Question:

The Wheatstone bridge is an arrangement of four resistances, say \(R_1, R_2, R_3\), and  \(R_4\). The null point condition is given by:

Updated On: Mar 27, 2025
  • \(\quad \frac{R_1}{R_2} = \frac{R_3}{R_4} \\\)
  • \(\quad R_1 + R_2 = R_3 + R_4 \\\)
  • \(\quad R_1 - R_2 = R_2 - R_4 \\\)
  • \(\quad R_1 \times R_2 = R_3 \times R_4\)
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The Correct Option is A

Approach Solution - 1

Four resistances arranged in a Wheatstone bridge configuration: \( R_1 \), \( R_2 \), \( R_3 \), \( R_4 \)

Null Point Condition:

The bridge is balanced when the potential difference between the midpoints is zero, which occurs when:

\[ \frac{R_1}{R_2} = \frac{R_3}{R_4} \]

This means the ratio of resistances in one arm equals the ratio in the opposite arm.

Option Analysis:

  1. Correct: \( \frac{R_1}{R_2} = \frac{R_3}{R_4} \) is the standard balance condition
  2. Incorrect: Sum of resistances doesn't determine balance
  3. Incorrect: Difference of resistances is irrelevant
  4. Incorrect: Product of resistances doesn't determine balance
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Approach Solution -2

The Wheatstone bridge is balanced when the ratio of the two resistances in one branch equals the ratio of the two resistances in the other branch:
\(\quad \frac{R_1}{R_2} = \frac{R_3}{R_4} \\\)This is the condition for zero current through the galvanometer.
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