The mass density \( \rho \) of a nucleus is defined as:
\[
\rho = \frac{\text{Mass}}{\text{Volume}}.
\]
The mass of the nucleus is proportional to the mass number \( A \), so:
\[
\text{Mass} \propto A.
\]
The volume of a nucleus is proportional to the cube of its radius, and the radius of the nucleus \( R \) is proportional to \( A^{1/3} \). Thus, the volume \( V \) of the nucleus is:
\[
V \propto R^3 \propto A.
\]
Therefore, the mass density \( \rho \) is given by:
\[
\rho = \frac{\text{Mass}}{\text{Volume}} \propto \frac{A}{A} = A^{1/3}.
\]
Thus, the correct answer is (1) \( \rho \propto A^{1/3} \).