Question:

For a nucleus of mass number $A$ and radius $R$, mass density $\rho$. Then choose the correct option.

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The mass density of a nucleus is inversely proportional to the cube of the radius, and the radius is proportional to \( A^{1/3} \).
Updated On: Apr 12, 2025
  • \( \rho \propto A^{1/3} \)
  • \( \rho \) is independent of \( A \)
  • \( \rho \propto A \)
  • \( \rho \propto A^3 \)
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The Correct Option is A

Solution and Explanation


The mass density \( \rho \) of a nucleus is defined as: \[ \rho = \frac{\text{Mass}}{\text{Volume}}. \] The mass of the nucleus is proportional to the mass number \( A \), so: \[ \text{Mass} \propto A. \] The volume of a nucleus is proportional to the cube of its radius, and the radius of the nucleus \( R \) is proportional to \( A^{1/3} \). Thus, the volume \( V \) of the nucleus is: \[ V \propto R^3 \propto A. \] Therefore, the mass density \( \rho \) is given by: \[ \rho = \frac{\text{Mass}}{\text{Volume}} \propto \frac{A}{A} = A^{1/3}. \] Thus, the correct answer is (1) \( \rho \propto A^{1/3} \).
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