Question:

For a given velocity, a projectile has same range $R$ for two angles of projections. If $t_1$ and $t_2$ are the time of flight in the 2 cases then

Updated On: May 30, 2022
  • $t_1t_2\propto\frac{1}{R^2}$
  • $t_1t_2\propto\frac{1}{R}$
  • $t_1t_2\propto R$
  • $t_1t_2\propto R^2$
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The Correct Option is C

Solution and Explanation

R = $\frac{u^2 \, sin \, 2\theta_1}{g}$
$ = \frac{u^2 \, sin \, 2\theta_2}{g}$
Also, $\theta_1 + \theta_2 = 90^\circ $
i.e. $\theta_2 = 90^\circ - \theta_1$
Also, $t_1 = \frac{2u\, sin \, \theta_1}{g} $ and
$t_2 = \frac{2u\, sin \, \theta_2}{g}$
then
$t_1 \,t_2 = \frac{4u^2}{g^2} \, sin \, \theta_1 \, sin \, \theta_2$
i.e.
$t_1 \, t_2 = \frac{2}{g} \frac{u^2}{g} 2 \, sin \, \theta_1 \, sin (90 - \theta_1)$
$= \frac{2}{g} \frac{u^2}{g} 2 \, sin \, \theta_1 \, cos \, \theta_1$
$ = \frac{2}{g} \frac{u^2 \, sin \, 2\theta_1}{g}$
$ = \frac{2}{g}R$
i.e. $t_1 \, t_2 \propto R$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration