The critical angle (\(C\)) for total internal reflection is given by the relation:
\[ \sin C = \frac{1}{\mu} \]
where \( \mu \) is the refractive index of the denser medium relative to the rarer medium.
Important: Refractive index (\(\mu\)) varies with wavelength (colour) due to dispersion. For visible light, the refractive index is highest for violet (shortest wavelength) and lowest for red (longest wavelength).
Step-by-Step Logic:
\[ \sin C = \frac{1}{\mu} \]
Therefore, among visible colours, red will have the smallest refractive index, and thus the maximum critical angle.
The critical angle \( \theta_c \) for a pair of transparent media is given by the equation: \[ \sin \theta_c = \frac{n_2}{n_1} \] where:
\( n_1 \) is the refractive index of the denser medium,
\( n_2 \) is the refractive index of the rarer medium.
The critical angle depends on the refractive index of the medium. The refractive index decreases as the wavelength of light increases. Since red light has the longest wavelength and thus the smallest refractive index among the visible spectrum, the critical angle is the largest for red light.
Therefore, the critical angle for red light is maximum.
A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian.
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?