Let's analyze the output frequency of a full-wave rectifier.
1. Full-Wave Rectifier:
A full-wave rectifier converts both halves of an AC input waveform into a pulsating DC output waveform.
2. Input Frequency (fin):
The input frequency is given as 50 Hz.
3. Output Frequency (fout):
In a full-wave rectifier, both the positive and negative half-cycles of the input are converted to positive half-cycles in the output. This effectively doubles the frequency of the output waveform.
fout = 2 * fin
fout = 2 * 50 Hz
fout = 100 Hz
Therefore, the output frequency of a full-wave rectifier with an input frequency of 50 Hz is 100 Hz.
The correct answer is:
Option 2: 100 Hz
Match List-I with List-II:
List-I (Amplifiers) | List-II (Characteristics) |
---|---|
(A) CE Amplifier | (I) Current buffer circuit |
(B) CB Amplifier | (II) Voltage buffer circuit |
(C) CC Amplifier | (III) High current gain |
(D) Darlington Amplifier | (IV) High power gain |
Choose the correct answer:
Match List-I with List-II:
List-I (Effects) | List-II (Electronic Devices) |
---|---|
(A) Channel length modulation | (I) Zener diode |
(B) Channel width modulation | (II) BJTs |
(C) Early effect | (III) JFETs |
(D) Tunneling effect | (IV) MOSFETs |
Choose the correct answer:
Match List-I with List-II
List-I (Instructions) | List-II (Addressing Mode) |
---|---|
(A) LDA 2100 H | (I) Immediate |
(B) RAL | (II) Register |
(C) ADD C | (III) Direct |
(D) ANI 08 H | (IV) Implied |
Match List-I with List-II
List-I (Data Bus Status Output) | List-II (Status Signals) |
---|---|
(A) Memory read | (I) 0, 1, 1 |
(B) Op-code fetch | (II) 0, 1, 0 |
(C) INTR acknowledge | (III) 0, 0, 1 |
(D) Memory write | (IV) 1, 1, 1 |