Question:

For a first order reaction with rate constant of 230 s\(^{-1}\), the half-life is:

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For first-order reactions, remember the half-life formula \( t_{1/2} = \frac{0.693}{k} \). This is crucial when calculating half-life from the rate constant.
Updated On: Apr 6, 2025
  • \( 3.45 \times 10^{-2} \, \text{s} \)
  • \( 3.01 \times 10^{-2} \, \text{s} \)
  • \( 3.45 \times 10^{-3} \, \text{s} \)
  • \( 3.01 \times 10^{-3} \, \text{s} \)
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The Correct Option is D

Solution and Explanation

The half-life of a first-order reaction is given by the formula: \[ t_{1/2} = \frac{0.693}{k} \] where \( t_{1/2} \) is the half-life and \( k \) is the rate constant. Given \( k = 230 \, \text{s}^{-1} \), substituting this into the equation: \[ t_{1/2} = \frac{0.693}{230} = 3.01 \times 10^{-3} \, \text{s} \] Thus, the half-life is \( 3.01 \times 10^{-3} \, \text{s} \).
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