Question:
For a cell involving one electron \(E^\ominus cell=0.59V\) at 298 K, the equilibrium constant for the cell reaction is: [Given that \(\frac{ 2.303 RT }{F}\) \(=0.059 V\) at\( T 298 K \)]
For a cell involving one electron \(E^\ominus cell=0.59V\) at 298 K, the equilibrium constant for the cell reaction is: [Given that \(\frac{ 2.303 RT }{F}\) \(=0.059 V\) at\( T 298 K \)]
Updated On: May 21, 2024
- \(1.0\times 10^{2}\)
- \(1.0\times 10^{5}\)
- \(1.0\times 10^{10}\)
- \(1.0\times 10^{30}\)
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The Correct Option is C
Solution and Explanation
The correct option is (C) :\(1.0\times 10^{10}\)
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