Let the first number be x and the second number is 27 − x.
Therefore, their product = x (27 − x)
It is given that the product of these numbers is 182.
Therefore, x(27-x) = 182
⇒ \(x^2 -27x +182 = 0\)
⇒ \(x^2 - 13x -14x +182 =0\)
⇒ \(x(x-13) -14 (x-13) =0\)
⇒ \((x-13)(x-14) = 0\)
x – 13 = 0 or x − 14 = 0
i.e., x = 13 or x = 14
If first number = 13,then
Other number = 27 − 13 = 14
If first number = 14, then
Other number = 27 − 14 = 13
Therefore, the numbers are 13 and 14.
Solve the problems given in Example 1:-
(i) John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. Find out how many marbles they had to start with.
(ii) A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was Rs 750. Find out the number of toys produced on that day.
Find the roots of the following quadratic equations by factorisation:
(i) \(x^2 – 3x – 10 = 0\)
(ii) \(2x^2 + x – 6 = 0\)
(iii) \(\sqrt2x^2+7x+5\sqrt2 = 0\)
(iv) \(2x^2 – x + \frac{1}8\)\( = 0\)
(v) \(100x^2 – 20x + 1 = 0\)
सोलर पैनल वाली कंपनी 'उर्जा' की ओर से अपने उत्पाद की जानकारी देने और बिक्री बढ़ाने हेतु एक आकर्षक विज्ञापन तैयार कीजिए।
'एक कहानी यह भी' की लेखिका के जीवन पर उनकी प्राध्यापिका शीला अग्रवाल का क्या प्रभाव पड़ा ?