Let the radius of the sphere be r.
Surface area of sphere = 4\(\pi\)r2 = 154 cm2
Volume of a sphere = \(\frac{4}{3}\pi\)r3
\(⇒\) Surface area of the sphere = 4\(\pi\)r2 = 154cm²
r2 = \(\frac{154\ cm^2 }{ 4\pi}\)
r2 = (154 cm2) \(÷\) (4 × \(\frac{22}{7}\))
r = \(\sqrt{\frac{49}{4}}\)cm²
r = \(\frac{7}{2}\) cm
Now, radius of the sphere = \(\frac{7}{2}\) cm
So, volume of the sphere = \(\frac{4}{3}\pi\)r3
= \(\frac{4}{3}\) × \(\frac{22}{7}\) × \(\frac{7}{2}\) cm × \(\frac{7}{2}\) cm × \(\frac{7}{2}\) cm
= \(\frac{539}{3}\) cm3
Therefore, volume of the sphere is \(\frac{539}{3}\) cm3.

Section A | Section B | ||
|---|---|---|---|
Marks | Frequency | Marks | Frequency |
0 − 10 | 3 | 0 − 10 | 5 |
10 − 20 | 9 | 10 − 20 | 19 |
20 − 30 | 17 | 20 − 30 | 15 |
30 − 40 | 12 | 30 − 40 | 10 |
40 − 50 | 9 | 40 − 50 | 1 |
Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons compare the performance of the two sections.
(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)