Let the radius of the sphere be r.
Surface area of sphere = 4\(\pi\)r2 = 154 cm2
Volume of a sphere = \(\frac{4}{3}\pi\)r3
\(⇒\) Surface area of the sphere = 4\(\pi\)r2 = 154cm²
r2 = \(\frac{154\ cm^2 }{ 4\pi}\)
r2 = (154 cm2) \(÷\) (4 × \(\frac{22}{7}\))
r = \(\sqrt{\frac{49}{4}}\)cm²
r = \(\frac{7}{2}\) cm
Now, radius of the sphere = \(\frac{7}{2}\) cm
So, volume of the sphere = \(\frac{4}{3}\pi\)r3
= \(\frac{4}{3}\) × \(\frac{22}{7}\) × \(\frac{7}{2}\) cm × \(\frac{7}{2}\) cm × \(\frac{7}{2}\) cm
= \(\frac{539}{3}\) cm3
Therefore, volume of the sphere is \(\frac{539}{3}\) cm3.
List-I | List-II | ||
(A) | Volume of cone | (I) | \(\frac{1}{3}\pi h(r_1^2+r_2^2+r_1r_2)\) |
(B) | Volume of sphere | (II) | \(\frac{1}{3}\pi r^2h\) |
(C) | Volume of Frustum | (III) | \(\pi r^2h\) |
(D) | Volume of cylinder | (IV) | \(\frac{4}{3}\pi r^3\) |
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.