Let the radius of the sphere be r.
Surface area of sphere = 4\(\pi\)r2 = 154 cm2
Volume of a sphere = \(\frac{4}{3}\pi\)r3
\(⇒\) Surface area of the sphere = 4\(\pi\)r2 = 154cm²
r2 = \(\frac{154\ cm^2 }{ 4\pi}\)
r2 = (154 cm2) \(÷\) (4 × \(\frac{22}{7}\))
r = \(\sqrt{\frac{49}{4}}\)cm²
r = \(\frac{7}{2}\) cm
Now, radius of the sphere = \(\frac{7}{2}\) cm
So, volume of the sphere = \(\frac{4}{3}\pi\)r3
= \(\frac{4}{3}\) × \(\frac{22}{7}\) × \(\frac{7}{2}\) cm × \(\frac{7}{2}\) cm × \(\frac{7}{2}\) cm
= \(\frac{539}{3}\) cm3
Therefore, volume of the sphere is \(\frac{539}{3}\) cm3.
(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) ∆ ABD ≅ ∆ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.
