610
Step 1: Recall the formula for the sum of an arithmetic progression (AP):
The sum of the first \( n \) terms of an arithmetic progression is given by the formula:
\[ S_n = \frac{n}{2} \left[ 2a + (n-1) \cdot d \right] \]
Step 2: Identify the values from the given arithmetic progression:
Step 3: Substitute the values into the sum formula:
Substituting the values into the formula:
\[ S_{20} = \frac{20}{2} \left[ 2 \times 2 + (20-1) \cdot 3 \right] \]
\[ S_{20} = 10 \left[ 4 + 57 \right] \]
\[ S_{20} = 10 \times 61 = 610 \]
The sum of the first 20 terms of the arithmetic progression is 610. However, none of the provided options (400, 420, 440, or 460) match the calculated result, indicating a possible issue with the options.