Question:
Find the range of \(\frac{1}{7}-\sin5x\)
Find the range of \(\frac{1}{7}-\sin5x\)
Updated On: Apr 8, 2024
- \(\left[\frac{1}{7}, \frac{1}{5}\right]\)
- \(\left[\frac{1}{7}, \frac{1}{6}\right]\)
- \(\left[\frac{1}{8}, \frac{1}{5}\right]\)
- \(\left[\frac{1}{8}, \frac{1}{6}\right]\)
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The Correct answer is option is (D) : \(\left[\frac{1}{8}, \frac{1}{6}\right]\)
Was this answer helpful?
0
0
Top Questions on complex numbers
- Let \( z_1, z_2, z_3 \) be three complex numbers on the circle \( |z| = 1 \) with \( \arg(z_1) = -\frac{\pi}{4}, \arg(z_2) = 0 \) and \( \arg(z_3) = \frac{\pi}{4} \). If \( |z_1 \overline{z_2} + z_2 \overline{z_3} + z_3 \overline{z_1}|^2 = \alpha + \beta \sqrt{2} \), where \( \alpha, \beta \in \mathbb{Z} \), then the value of \( \alpha^2 + \beta^2 \) is :
- JEE Main - 2025
- Mathematics
- complex numbers
- Let integers \( a, b \in [-3, 3] \) be such that \( a + b \neq 0 \). \(\text{Then the number of all possible ordered pairs}\) \( (a, b) \), \(\text{for which}\) \[ \left| \frac{z - a}{z + b} \right| = 1 \quad \text{and} \quad \left| \begin{matrix} z + 1 & \omega & \omega^2 \\ \omega^2 & 1 & z + \omega \\ \omega^2 & 1 & z + \omega \end{matrix} \right| = 1, \] \(\text{is equal to:}\)
- JEE Main - 2025
- Mathematics
- complex numbers
- Let the curve \(z(1 + i) +\) \(\overline{z(1 - i) = 4}\), z \(\in\)\( \mathbb{C}\), divide the region \(|z - 3| \leq 1\) into two parts of areas \( \alpha \) and \( \beta \). Then \( |\alpha - \beta| \) equals:}
- JEE Main - 2025
- Mathematics
- complex numbers
- Let O be the origin, the point A be \( z_1 = \sqrt{3} + 2\sqrt{2}i \), the point B \( z_2 \) be such that \( \sqrt{3}|z_2| = |z_1| \) and \( \arg(z_2) = \arg(z_1) + \frac{\pi}{6} \). Then:
- JEE Main - 2025
- Mathematics
- complex numbers
- Let the curve \((\)\( z(1 + i) + \overline{z(1 - i)} = 4\), \(\, z \in \mathbb{C}\) \()\), divide the region \(|z - 3| \leq 1\) into two parts of areas \( \alpha \) and \( \beta \). Then \( |\alpha - \beta| \) equals:
- JEE Main - 2025
- Mathematics
- complex numbers
View More Questions
Questions Asked in JEE Main exam
- In YDSE, light of intensity \( 4I \) and \( 9I \) passes through two slits respectively. Difference of maximum and minimum intensity of interference pattern is:
- JEE Main - 2025
- Wave optics
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
- JEE Main - 2025
- Differential Equations
Find the IUPAC name of the compound.
- JEE Main - 2025
- Aromaticity & chemistry of aromatic compounds
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32
- JEE Main - 2025
- Limits and Exponential Functions
- The integral \[ \int_0^\pi \frac{8x}{4\cos^2 x + \sin^2 x} \, dx \text{ is equal to:} \]
- JEE Main - 2025
- Trigonometric Functions
View More Questions