Find the number of natural numbers less than (or up to) 1000 having different digits.
Question:

Find the number of natural numbers less than (or up to) 1000 having different digits.

Updated On: May 11, 2024
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Solution and Explanation

One Digit numbers = 9
Two Digit numbers = 10P2 - 9P1
= 90 - 9
= 81
Three Digit numbers = 10P3 - 9P2
= 720 - 72
= 648
Therefore , Total = 9 + 81 + 648 = 738

So, the answer is 738.

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