(i) By placing bars, we obtain
\(64=\bar{64}\)
Since there is only one bar, the square root of \(64\) will have only one digit in it.
(ii) By placing bars, we obtain
\(144=\bar1 \bar{44}\)
Since there are two bars, the square root of \(144\) will have \(2\) digits in it.
(iii) By placing bars, we obtain
\(4489=\bar{44}\bar{ 89}\)
Since there are two bars, the square root of \(4489\) will have \(2\) digits in it.
(iv) By placing bars, we obtain
\(27225 = \bar2 \,\bar{72} \,\bar{25}\)
Since there are three bars, the square root of \(27225\) will have three digits in it.
(v) By placing the bars, we obtain
\(390625= \bar{39} \;\bar{06}\; \bar{25}\)
Since there are three bars, the square root of \(390625\) will have \(3\) digits in it.