Find the median of the following distribution table: 
Step 1: Find cumulative frequency (CF). 
Step 2: Identify the median class.
Total frequency \( n = 18 \). \[ \dfrac{n}{2} = 9 \] The median class is the class where cumulative frequency ≥ 9, i.e., \( 20 - 30 \).
Step 3: Apply the formula.
\[ \text{Median} = L + \left(\dfrac{\dfrac{n}{2} - CF_{before}}{f}\right) \times h \] Here, \( L = 20, CF_{before} = 6, f = 7, h = 10 \). \[ \text{Median} = 20 + \left(\dfrac{9 - 6}{7}\right) \times 10 = 20 + \dfrac{30}{7} = 24.3 \]
Step 4: Conclusion.
Hence, the median of the data is approximately 24.3.
Scores obtained by two students P and Q in seven courses are given in the table below. Based on the information given in the table, which one of the following statements is INCORRECT?
