Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.
The given data is
38, 70, 48, 40, 42, 55, 63, 46, 54, 44
Mean of the given data,
\(\bar{x}=\frac{38+70+48+40+42+55+63+46+54+44}{10}=\frac{500}{10}=50\)
The deviations of the respective observations from the mean \(\bar{x},i.e.x_i-\bar{x}\) are
12, 20, 2, 10, 8, 5, 13, 4, 4, 6
The absolute values of the deviations, i.e. \(|x_i-\bar{x}|\), are
12, 20, 2, 10, 8, 5, 13, 4, 4, 6
The required mean deviation about the mean is \(M.D(\bar{x})=\frac{\sum_{i=1}^{8}|x_i-\bar{x}|}{10}\)
\(=\frac{12+20+2+10+8+5+13+4+4+6}{10}\)
\(=\frac{84}{10}\)
\(=8.4\)
What inference do you draw about the behaviour of Ag+ and Cu2+ from these reactions?
A statistical measure that is used to calculate the average deviation from the mean value of the given data set is called the mean deviation.
The mean deviation for the given data set is calculated as:
Mean Deviation = [Σ |X – µ|]/N
Where,
Grouping of data is very much possible in two ways: