Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.
The given data is
38, 70, 48, 40, 42, 55, 63, 46, 54, 44
Mean of the given data,
\(\bar{x}=\frac{38+70+48+40+42+55+63+46+54+44}{10}=\frac{500}{10}=50\)
The deviations of the respective observations from the mean \(\bar{x},i.e.x_i-\bar{x}\) are
12, 20, 2, 10, 8, 5, 13, 4, 4, 6
The absolute values of the deviations, i.e. \(|x_i-\bar{x}|\), are
12, 20, 2, 10, 8, 5, 13, 4, 4, 6
The required mean deviation about the mean is \(M.D(\bar{x})=\frac{\sum_{i=1}^{8}|x_i-\bar{x}|}{10}\)
\(=\frac{12+20+2+10+8+5+13+4+4+6}{10}\)
\(=\frac{84}{10}\)
\(=8.4\)
Class | 0 – 15 | 15 – 30 | 30 – 45 | 45 – 60 | 60 – 75 | 75 – 90 |
---|---|---|---|---|---|---|
Frequency | 11 | 8 | 15 | 7 | 10 | 9 |
Variance of the following discrete frequency distribution is:
\[ \begin{array}{|c|c|c|c|c|c|} \hline \text{Class Interval} & 0-2 & 2-4 & 4-6 & 6-8 & 8-10 \\ \hline \text{Frequency (}f_i\text{)} & 2 & 3 & 5 & 3 & 2 \\ \hline \end{array} \]
A statistical measure that is used to calculate the average deviation from the mean value of the given data set is called the mean deviation.
The mean deviation for the given data set is calculated as:
Mean Deviation = [Σ |X – µ|]/N
Where,
Grouping of data is very much possible in two ways: