(i) 28.7 pm:
1 pm = 10-12 m
∴ 28.7 pm = 28.7 × 10-12 m
= 2.87 × 10-11 m
(ii) 15.15 pm:
1 pm = 10-12 m
∴ 15.15 pm = 15.15 × 10-12 m
= 1.515 × 10-11 m
(iii) 25365 mg:
1 mg = 10-3 g
25365 mg = 2.5365 × 104 × 10-3 g
Since,
1 g = 10-3 kg
2.5365 × 101 g = 2.5365 × 101 × 10-3 kg
∴ 25365 mg = 2.5365 × 10-2 kg
| LIST I | LIST II | ||
| A. | \(K_2SO_4(aq)\) with 60% dissociation | I. | \(i =3.7\) |
| B. | \(K_3[Fe(CN)_6](aq)\) with 90% dissociation | II. | \(i= 1.8\) |
| C. | \(AlCl_3 (aq)\) with 80% dissociation | III. | \(i=2.2\) |
| D. | \(K_2HgI_4 (aq)\) with 40% dissociation | IV. | \(i= 3.4\) |
What is the percentage of carbon in ethanol (\(C_{2}H_{5}OH\)) ?
(Atomic masses: C = 12, H = 1, O = 16)
Figure 8.9 shows the strain-stress curve for a given material. What are (a) Young’s modulus and (b) approximate yield strength for this material?

Two identical ball bearings in contact with each other and resting on a frictionless table are hit head-on by another ball bearing of the same mass moving initially with a speed V. If the collision is elastic, which of the following (Fig. 5.14) is a possible result after collision ?

Read More: Some Basic Concepts of Chemistry
There are two ways of classifying the matter:
Matter can exist in three physical states:
Based upon the composition, matter can be divided into two main types: