Find the mean and mode of the following data:
Class | 15--20 | 20--25 | 25--30 | 30--35 | 35--40 | 40--45 |
Frequency | 12 | 10 | 15 | 11 | 7 | 5 |
Given Data:
Class | 15–20 | 20–25 | 25–30 | 30–35 | 35–40 | 40–45 |
---|---|---|---|---|---|---|
Frequency (f) | 12 | 10 | 15 | 11 | 7 | 5 |
Step 1: Find the mid-point (x) of each class interval
Mid-point \( x = \frac{\text{Lower limit} + \text{Upper limit}}{2} \)
Class | Mid-point (x) |
---|---|
15 – 20 | 17.5 |
20 – 25 | 22.5 |
25 – 30 | 27.5 |
30 – 35 | 32.5 |
35 – 40 | 37.5 |
40 – 45 | 42.5 |
Step 2: Calculate \( f \times x \) for each class
Class | Frequency (f) | Mid-point (x) | f × x |
---|---|---|---|
15 – 20 | 12 | 17.5 | 210 |
20 – 25 | 10 | 22.5 | 225 |
25 – 30 | 15 | 27.5 | 412.5 |
30 – 35 | 11 | 32.5 | 357.5 |
35 – 40 | 7 | 37.5 | 262.5 |
40 – 45 | 5 | 42.5 | 212.5 |
Step 3: Find total frequency and total \( f \times x \)
Total frequency, \( \sum f = 12 + 10 + 15 + 11 + 7 + 5 = 60 \)
Total \( f \times x \), \( \sum f x = 210 + 225 + 412.5 + 357.5 + 262.5 + 212.5 = 1680 \)
Step 4: Calculate Mean
Mean \(= \frac{\sum f x}{\sum f} = \frac{1680}{60} = 28\)
Step 5: Find the Mode
Mode formula for grouped data:
Mode \(= l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h\)
Where:
- \( l \) = lower boundary of modal class
- \( f_1 \) = frequency of modal class
- \( f_0 \) = frequency of class before modal class
- \( f_2 \) = frequency of class after modal class
- \( h \) = class width
Step 6: Identify Modal Class
The modal class is the class with the highest frequency.
Frequencies: 12, 10, 15, 11, 7, 5
Highest frequency = 15, so modal class = 25 – 30
Step 7: Apply values in mode formula
- \( l = 25 \) (lower limit of modal class)
- \( f_1 = 15 \)
- \( f_0 = 10 \) (frequency before modal class)
- \( f_2 = 11 \) (frequency after modal class)
- \( h = 5 \) (class width)
Step 8: Calculate Mode
Mode \(= 25 + \left( \frac{15 - 10}{2 \times 15 - 10 - 11} \right) \times 5 = 25 + \left( \frac{5}{30 - 10 - 11} \right) \times 5 = 25 + \left( \frac{5}{9} \right) \times 5 = 25 + \frac{25}{9} = 25 + 2.78 = 27.78\)
Final Answer:
Mean = 28
Mode = 27.78
There is a circular park of diameter 65 m as shown in the following figure, where AB is a diameter. An entry gate is to be constructed at a point P on the boundary of the park such that distance of P from A is 35 m more than the distance of P from B. Find distance of point P from A and B respectively.