Question

Find the intercepts made by the line 3x + 4y - 12 = 0 on the axes:

• A. 2 and 3
• B. 4 and 3
• C. 3 and 5
• D. None of these

Answer 1

The Correct Option is B

The line given is $3x+4y-12=0$. To find the intercepts, we need to find where this line crosses the axes.

X-intercept: Set $y=0$ in the equation:

$3x+4\left(0\right)-12=0$

$3x-12=0$

$3x=12$

$x=4$

Thus, the x-intercept is $(4,0)$.

Y-intercept: Set $x=0$ in the equation:

$3\left(0\right)+4y-12=0$

$4y-12=0$

$4y=12$

$y=3$

Thus, the y-intercept is $(0,3)$.

The intercepts made on the axes are 4 and 3, which matches the option 4 and 3.