Substituting n = 20, we obtaina20 = 20\(\frac{(20-2)}{20+3}\)
= 20\(\frac{(18)}{23}\)
= \(\frac{360}{23}\)
Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.