Given that, Length of major axis \(= 26\) ; foci \(= ( ±5, 0)\)
Since the foci are on the x-axis, the major axis is along the x-axis.
Therefore, the equation of the ellipse will be of the form \(\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1\), where a is the semi-major axis.
Accordingly, \(2a = 26\)
\(⇒ a = 13\) and \(c = 5.\)
It is known that
\(a^2 = b^2 + c^2.\)
\(13^2 = b^2+5^2\)
\(169 = b^2 + 25\)
\(b^2 = 169 – 25\)
\(b = √144\)
\(= 12\) (Ans.)
Thus, the equation of the ellipse is \(\dfrac{x^2}{13^2} + \dfrac{y^2}{12^2} = 1\) or \(\dfrac{x^2}{169} + \dfrac{y^2}{144} = 1\) (Ans.)
Figures 9.20(a) and (b) refer to the steady flow of a (non-viscous) liquid. Which of the two figures is incorrect ? Why ?
An ellipse is a locus of a point that moves in such a way that its distance from a fixed point (focus) to its perpendicular distance from a fixed straight line (directrix) is constant. i.e. eccentricity(e) which is less than unity
Read More: Conic Section
The ratio of distances from the center of the ellipse from either focus to the semi-major axis of the ellipse is defined as the eccentricity of the ellipse.
The eccentricity of ellipse, e = c/a
Where c is the focal length and a is length of the semi-major axis.
Since c ≤ a the eccentricity is always greater than 1 in the case of an ellipse.
Also,
c2 = a2 – b2
Therefore, eccentricity becomes:
e = √(a2 – b2)/a
e = √[(a2 – b2)/a2] e = √[1-(b2/a2)]
The area of an ellipse = πab, where a is the semi major axis and b is the semi minor axis.
Let the point p(x1, y1) and ellipse
(x2 / a2) + (y2 / b2) = 1
If [(x12 / a2)+ (y12 / b2) − 1)]
= 0 {on the curve}
<0{inside the curve}
>0 {outside the curve}