Question:

Find the derivative of xn + ax n-1 + a2xn-2+……...+a n-1x + an for some fixed real number a.

Updated On: Oct 25, 2023
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

Let f'(x): = xn + ax n-1 + a2xn-2+……...+a n-1x + an
∴f(x)=\(\frac{d}{dx}\)(xn + ax n-1 + a2xn-2+……...+a n-1x + an)
=\(\frac{d}{dx}\)(xn) + a\(\frac{d}{dx}\)(xn-1) + a2\(\frac{d}{dx}\)(xn-2) + …..... + an-1\(\frac{d}{dx}\)(x) + a\(\frac{d}{dx}\)(1) 
On using theorem \(\frac{d}{dx}\)x
= nxn-1, we obtain f'(x)=nxn-1 +a(n-1)xn-2 + a2 (n-2)xn-3 +...+an-1+an (0)
=nxn-1+ a(n-1)xn-2+a2(n-2)xn-3 +...+an-1
Was this answer helpful?
0
0