Question:

Find the derivative of $\frac{x^{5}-cos\,x}{sin\,x}$.

Updated On: Jul 6, 2022
  • $\frac{x^{5}\,cos\,x}{sin^{2}\,x}$
  • $\frac{1}{sin\,x}-\frac{x^{5}\,cos\,x}{sin^{2}\,x}$
  • $\frac{x}{sin^{2}\,x}$
  • None of these
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The Correct Option is D

Solution and Explanation

Let $f\left(x\right)=\frac{x^{5}-cos\,x}{sin\,x}$ $f'\left(x\right)=\frac{\left(x^{5}-cos\,x\right)'sin\,x-\left(x^{5}-cos\,x\right)\left(sin\,x\right)'}{\left(sin\,x\right)^{2}}$ $\{$using quotient rule$\}$ $=\frac{\left(5x^{4}+sin\,x\right)sin\,x-\left(x^{5}-cos\,x\right)cos\,x}{sin^{2}\,x}$ $=\frac{-x^{5}\,cos\,x+5x^{4}\,sin\,x+1}{sin^{2}\,x}$
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