The x-axis divides the line segment joining two points in such a way that the y-coordinate of the point is 0.
Let the required point be \( P(x, 0) \). We can use the section formula to find the coordinates of this point. The section formula for a point dividing a line segment in the ratio \( m:n \) is given by:
\[
x = \frac{m x_2 + n x_1}{m + n}, \quad y = \frac{m y_2 + n y_1}{m + n}.
\]
In this case, the point \( P \) divides the segment joining \( (1, -5) \) and \( (-4, 5) \) in the ratio \( m:n = 1:1 \) (since the point lies on the x-axis). Therefore, the coordinates of point \( P \) are:
\[
x = \frac{1 \times (-4) + 1 \times 1}{1 + 1} = \frac{-4 + 1}{2} = \frac{-3}{2} = -1.5.
\]
\[
y = \frac{1 \times 5 + 1 \times (-5)}{1 + 1} = \frac{5 - 5}{2} = 0.
\]
Thus, the coordinates of the point are \( (-1.5, 0) \).
Conclusion:
The coordinates of the point are \( (-1.5, 0) \).