Question:

Find the area of the region bounded by curves \(y=x^2+2,y=x,x=0\) and \(x=3\)

Updated On: Sep 18, 2023
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Solution and Explanation

The correct answer is:\(\frac{21}{2}units.\)
The area bounded by the curves,\(y=x^2+2,y=x,x=0,\)and \(x=3\),is represented by
the shaded area OCBAO as
Area bounded
Then,Area OCBAO=Area ODBAO-Area ODCO
\(=∫^3_0(x^2+2)dx-∫^3_0xdx\)
\(=[\frac{x^3}{3}+2x]^3_0-[\frac{x^2}{2}]^3_0\)
\(=[9+6]-[\frac{9}{2}]\)
\(=15-\frac{9}{2}\)
\(=\frac{21}{2}units.\)
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Concepts Used:

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