Question:
Find the area of a trapezoid with bases of 6 cm and 10 cm, and height of 4 cm.
Find the area of a trapezoid with bases of 6 cm and 10 cm, and height of 4 cm.
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The area of a trapezoid is given by the average of the two bases multiplied by the height. Always double-check your calculation of the bases and height!
Updated On: Oct 6, 2025
- \( 24 \, \text{cm}^2 \)
- \( 28 \, \text{cm}^2 \)
- \( 32 \, \text{cm}^2 \)
- \( 36 \, \text{cm}^2 \)
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The Correct Option is C
Solution and Explanation
We are asked to find the area of a trapezoid. The formula for the area of a trapezoid is:
\[
\text{Area} = \frac{1}{2} \times ( \text{base}_1 + \text{base}_2 ) \times \text{height}.
\]
In this problem, the given values are:
- Base 1 (\( \text{base}_1 \)) = 6 cm,
- Base 2 (\( \text{base}_2 \)) = 10 cm,
- Height (\( \text{height} \)) = 4 cm.
Substitute the values into the formula:
\[
\text{Area} = \frac{1}{2} \times (6 + 10) \times 4.
\]
Simplify the expression:
\[
\text{Area} = \frac{1}{2} \times 16 \times 4.
\]
First, multiply the bases:
\[
6 + 10 = 16.
\]
Now, calculate:
\[
\frac{1}{2} \times 16 = 8,
\]
and then multiply by the height:
\[
8 \times 4 = 32.
\]
Thus, the area of the trapezoid is:
\[
\boxed{32 \, \text{cm}^2}.
\]
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