Question

Find the amount of water displaced by a solid spherical ball of diameter.
(i) 28 cm 
(ii) 0.21 m

Answer 1

(i) Radius of the ball, r = \(\frac{28}{2}\) cm = 14cm
volume of the ball = \(\frac{4}{3}\pi r^3\)
= \(\frac{4}{3} ×\frac{ 22}{7}\) \(× 14\) cm \(× 14\) cm \(× 14\) cm

\(= \frac{34496}{3}\) cm³
= 11498.66 cm³

---

(ii) Radius of the ball, r =\(\frac{0.21}{2}\) m = 0.105 m
volume of a ball = \(\frac{4}{3}\pi r^3\)
= \(\frac{4}{3} ×\frac{ 22}{7}\) \(× 0.105\) m \(× 0.105\) m \(× 0.105\) m
= 0.004851 m³