(i) Radius of the ball, r = \(\frac{28}{2}\) cm = 14cm
volume of the ball = \(\frac{4}{3}\pi r^3\)
= \(\frac{4}{3} ×\frac{ 22}{7}\) \(× 14\) cm \(× 14\) cm \(× 14\) cm
\(= \frac{34496}{3}\) cm3
= 11498.66 cm3
(ii) Radius of the ball, r =\(\frac{0.21}{2}\) m = 0.105 m
volume of a ball = \(\frac{4}{3}\pi r^3\)
= \(\frac{4}{3} ×\frac{ 22}{7}\) \(× 0.105\) m \(× 0.105\) m \(× 0.105\) m
= 0.004851 m3
When 3.0g of carbon is burnt in 8.00g oxygen, 11.00g of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00g of carbon is burnt in 50.0g of oxygen? Which law of chemical combination will govern your answer?