Question:

Find \( \tan^{-1} (-\sqrt{3}) \).

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The inverse tangent of a negative value is the negative of the corresponding positive angle.
  • \( \frac{\pi}{6} \)
  • \( \frac{\pi}{3} \)
  • \( \frac{2\pi}{3} \)
  • \( -\frac{\pi}{3} \)
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The Correct Option is D

Solution and Explanation

We are asked to find: \[ \tan^{-1} (-\sqrt{3}) \] We know that: \[ \tan \frac{\pi}{3} = \sqrt{3} \] Since the argument is negative, we are looking for the angle in the fourth quadrant. The value of \( \tan^{-1} (-\sqrt{3}) \) is: \[ -\frac{\pi}{3} \] Thus, the correct answer is \( -\frac{\pi}{3} \).
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