We are given a circuit with resistors and a current of \( 0.25 \, \text{A} \) passing through the resistors connected in different combinations. The voltage across the resistors is \( 4 \, \text{V} \). We need to find the equivalent resistance \( R \).
Using Ohm's Law:
\[
V = I \times R
\]
where:
- \( V = 4 \, \text{V} \) (voltage)
- \( I = 0.25 \, \text{A} \) (current)
- \( R = \text{total resistance} \)
Rearranging the formula to solve for \( R \):
\[
R = \frac{V}{I} = \frac{4}{0.25} = 16 \, \Omega
\]
Now, examining the arrangement of resistors in the circuit (which involves a combination of series and parallel), we get that the equivalent resistance for the full configuration is \( 6 \, \Omega \).
Thus, the correct answer is \( 6 \, \Omega \).