Question:
Find \( P(G \cap \overline{H}) \), where \( G \) is the event of Jaspreet's selection and \( \overline{H} \) denotes the event that Rohit is not selected.
Find \( P(G \cap \overline{H}) \), where \( G \) is the event of Jaspreet's selection and \( \overline{H} \) denotes the event that Rohit is not selected.
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For independent events, the probability of their intersection is the product of their individual probabilities.
Updated On: Feb 19, 2025
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Solution and Explanation
\( P(G | \overline{H}) \) is the conditional probability of \( G \) given \( \overline{H} \).
\( P(G \cap \overline{H}) \) is the probability that both \( G \) and \( \overline{H} \) occur.
\( P(\overline{H}) \) is the probability that \( H \) does not occur.
\[ P(G | \overline{H}) = \frac{P(G \cap \overline{H})}{P(\overline{H})} = \frac{1}{3} \]Was this answer helpful?
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