Question:

Find $ P(G \cap \overline{H}) $, where $ G $ is the event of Jaspreet's selection and $ \overline{H} $ denotes the event that Rohit is not selected.

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For independent events, the probability of their intersection is the product of their individual probabilities.

Updated On: Jan 13, 2026

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$ P(G | \overline{H}) $ is the conditional probability of $ G $ given $ \overline{H} $.

$ P(G \cap \overline{H}) $ is the probability that both $ G $ and $ \overline{H} $ occur.

$ P(\overline{H}) $ is the probability that $ H $ does not occur.

\[ P(G | \overline{H}) = \frac{P(G \cap \overline{H})}{P(\overline{H})} = \frac{1}{3} \]

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X	0	1	2	3	4	5	6	7
P(x)	0	k	2k	2k	3k	k²	2k²	7k² + k

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