Step 1: Consider the given limit \( \lim_{x \to 0} \frac{| \sin x |}{x} \).
For \( x \to 0^+ \) (approaching 0 from the right), \( \sin x \) is positive, so \( | \sin x | = \sin x \).
The limit becomes: \[ \lim_{x \to 0^+} \frac{\sin x}{x} = 1. \] For \( x \to 0^- \) (approaching 0 from the left), \( \sin x \) is negative, so \( | \sin x | = -\sin x \). The limit becomes: \[ \lim_{x \to 0^-} \frac{-\sin x}{x} = -1. \]
Since the limit from the right is 1 and the limit from the left is -1, the two one-sided limits are not equal.
Hence, the limit does not exist.
Let $\alpha,\beta\in\mathbb{R}$ be such that the function \[ f(x)= \begin{cases} 2\alpha(x^2-2)+2\beta x, & x<1 \\ (\alpha+3)x+(\alpha-\beta), & x\ge1 \end{cases} \] is differentiable at all $x\in\mathbb{R}$. Then $34(\alpha+\beta)$ is equal to}