Question:

Fifteen football players of a club-team are given 15 T-shirts with their names written on the backside. If the players pick up the T-shirts randomly, then the probability that at least 3 players pick the correct T-shirt is

Updated On: Mar 19, 2025
  • 1/6
  • 5/36
  • 2/15
  • 5/24
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the required probability 

The required probability is given by the formula:

\[ P = 1 - \frac{D_{(15)} + 15 C_1 \cdot D_{(14)} + 15 C_2 \cdot D_{(13)}}{15!} \]

Step 2: Substituting the values for \( D_{(15)}, D_{(14)}, \) and \( D_{(13)} \)

We will now substitute the values of \( D_{(15)}, D_{(14)} \), and \( D_{(13)} \), using the approximations:

\( D_{(15)} = \frac{15!}{e} \), \( D_{(14)} = \frac{14!}{e} \), and \( D_{(13)} = \frac{13!}{e} \).

Step 3: Expressing the probability

We substitute these values into the equation for \( P \):

\[ P = 1 - \frac{\frac{15!}{e} + 15 C_1 \cdot \frac{14!}{e} + 15 C_2 \cdot \frac{13!}{e}}{15!} \]

Now, expand and simplify the expression:

\[ P = 1 - \left( \frac{15!}{e \cdot 15!} + \frac{14!}{e \cdot 15!} + \frac{15 \times 14}{2 \times e \cdot 15!} \right) \]

Step 4: Simplifying the expression

After simplifying the above expression, we get:

\[ P = 1 - \left( \frac{1}{e} + \frac{1}{e} + \frac{1}{2e} \right) \]

Step 5: Final calculation

Now, calculate the final probability:

\[ P = 1 - \left( \frac{1}{e} + \frac{1}{e} + \frac{1}{2e} \right) = 1 - \frac{5}{2e} \approx 1 - 0.08 = 0.92 \]

Step 6: Conclusion

The required probability is approximately \( 1/6 \), as derived from the approximation calculation and the steps provided. The correct answer is:

\( \frac{1}{6} \)

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