\(FeSO_4\) solution mixed with\( (NH_4)_2SO_4 \) solution in\( 1:1\) molar ratio gives the test of \(Fe^{2+}\) ion but \(CuSO_4\) solution mixed with aqueous ammonia in \( 1:4 \) molar ratio does not give the test of \(Cu^{2+}\) ion. Explain why?
\((NH_4)_2SO_4+FeSO_4+6H_2O→FeSO_4.(NH_4)_2SO_4.6H_2O \)
\(Mohr's salt\)
\(CuSO_4+4NH_3+5H_2O→[Cu(NH_3)_4]SO_4.5H_2O\)
\( tetraaminocopper(ii)sulphate\)
Both the compounds i.e.,\(FeSO_4.(NH_4)_2SO_4.6H_2O\) and \( [Cu(NH_3)_4]SO_4.5H_2O \) fall under the category of addition compounds with only one major difference i.e., the former is an example of a double salt, while the latter is a coordination compound. A double salt is an addition compound that is stable in the solid state but that which breaks up into its constituent ions in the dissolved state. These compounds exhibit individual properties of their constituents. For e.g \(FeSO_4.(NH_4)_2SO_4.6H_2O\) breaks into \(Fe^{2+}, NH^{4+}\), and \((SO_4)^{ 2-} \) ions. Hence, it gives a positive test for \(Fe ^{2+}\) ions. A coordination compound is an addition compound which retains its identity in the solid as well as in the dissolved state. However, the individual properties of the constituents are lost. This happens because. \([Cu(NH_3)_4]SO_4.5H_2O\) does not show the test for \(Cu ^{2+}\). The ions present in the solution of \([Cu(NH_3)_4]SO_4.5H_2O\) are \([Cu(NH_3)_4]^{2+}\) and \(SO_4^{2-}\)
Simar, Tanvi and Umara were partners in a firm sharing profits and losses in the ratio of 5:6:9. On 31st March, 2024 their Balance Sheet was as follows:
Umara died on 30th June, 2024. The partnership deed provided for the following on the death of a partner:
Write a letter to the editor of a local newspaper expressing your concerns about the increasing “Pollution levels in your city”. You are an environmentalist, Radha/Rakesh, 46, Peak Colony, Haranagar. You may use the following cues along with your own ideas: