Δ=|x y x+y y x+y x x+y x y|
Applying R1→R1+R2+R3,we have
Δ=|2(x+y) 2(x+y) 2(x+y) y x+y x x+y x y|
=2(x+y)|111 y x+y x x+y x y|
Applying C2→C2-C1 and C3→C3-C1,we have
Δ=2(x+y)|100 y x x-y x+y -y -x|
Expanding along R1, we have:
Δ=2(x+y)[-x2+y(x-y)]
=-2(x+y)(x2+y2-yx)
=-2(x3+y3)
If \(\begin{vmatrix} 2x & 3 \\ x & -8 \\ \end{vmatrix} = 0\), then the value of \(x\) is:
Let I be the identity matrix of order 3 × 3 and for the matrix $ A = \begin{pmatrix} \lambda & 2 & 3 \\ 4 & 5 & 6 \\ 7 & -1 & 2 \end{pmatrix} $, $ |A| = -1 $. Let B be the inverse of the matrix $ \text{adj}(A \cdot \text{adj}(A^2)) $. Then $ |(\lambda B + I)| $ is equal to _______
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]
Balance Sheet of Chandan, Deepak and Elvish as at 31st March, 2024
Liabilities | Amount (₹) | Assets | Amount (₹) |
---|---|---|---|
Capitals: | Fixed Assets | 27,00,000 | |
Chandan | 7,00,000 | Stock | 3,00,000 |
Deepak | 5,00,000 | Debtors | 2,00,000 |
Elvish | 3,00,000 | Cash | 1,00,000 |
General Reserve | 4,50,000 | ||
Creditors | 13,50,000 | ||
Total | 33,00,000 | Total | 33,00,000 |