At x = 2, the value of the given rational function takes the form 0/0 \(\lim_{x\rightarrow 2}\)\(\frac{3x^2-x-10}{x^2-4}\) =\(\lim_{x\rightarrow 2}\)\(\frac{(x-2)(3x+5)}{(x-2)(x+2)}\) \(\lim_{x\rightarrow 2}\)\(\frac{3x+5}{x+2}\) =\(\frac{3(2)+5}{2+2}\) =\(\frac{11}{4}\)