At x = -2, the value of the given function takes the form 0/0. \(\lim_{x\rightarrow -2}\)\(\frac{\frac{1}{x}+\frac{1}{2}}{x+2}\)=\(\lim_{x\rightarrow -2}\)\(\frac{\frac{2+x}{2x}}{x+2}\) = \(\lim_{x\rightarrow -2}\)\(\frac{1}{2x}\) = \(\frac{1}{2(-2)}\) = \(-\frac{1}{4}\)